Robert Hamilton
DeVry University
Serial RL Circuit Analysis
For week ii iLab, our objectives were to analyze an AC circuit in series with the succeeding(a) subdivisions: 47mH inductor with internal resistance and a 470 ? resistor. Each component pull up stakes experience certain voltage drops and current alternations delinquent to the frequency changes. The circuit was conducted at 1 kHz, 2 kHz, and 3 kHz. Given the initial conditions, we measured voltage across the components accordingly. We were in like manner able to measure the current through the components as well. later the construction of the circuit, the simulation of the circuit followed. Overall, the iLab conducts current, voltage measurements in a series circuit.
Impedance of Each Component at 1 kHz
At the beginning of lab, you are given questions that require debate written calculations. First, you obligate to calculate the resistance of the inductor in the series circuit. Before you calculate impedance for the inductor component, you oblige to measure its internal resistance. In the real world, the inductor will have an internal resistance so the formula was meagerly adjusted. For the 470 ? resistor, the formula remained the same.
* RL+jXL = Z1 = 74 ? + j295 = Inductor impedance
* R+j0 = Z2 = 470 ? + j0 = Resistors impedance
Total impedance and Current
Once we have calculated the required nurture, we can put one over it to solve for tote up impedance and total current in the series circuit. In order to solve for total impedance, you have to put the information in rectangular form first. The information above has already been converted to rectangular form so we just have to add them together to obtain total impedance. To determine the current through a certain component, we uptake a certain formula. This formula states that Vs/ZT will give you current.
* ZT = Z1 + Z2 = (74 ? + j295) + (470 ? + j0) = 544 ? + j295
* I@1 kHz = Vs/ZT = 2.5VRMS/544 ?
Voltage Drops for Each...If you want to get a full essay, order it on our website: Orderessay
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